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fix possible to choose more than 1 notarisation

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This commit is contained in:
blackjok3r
2019-02-07 00:00:11 +08:00
parent e2e7614dff
commit cfef67c59b
2 changed files with 17 additions and 7 deletions
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8
src/komodo_bitcoind.h
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@@ -1777,14 +1777,20 @@ int32_t komodo_notarized_height(int32_t *prevMoMheightp,uint256 *hashp,uint256 *
uint64_t komodo_notarypayamount(int32_t height, int64_t numnotaries)
{
if ( numnotaries == 0 )
{
fprintf(stderr, "komodo_notarypayamount failed num notaries is 0!\n");
return(0);
}
// fetch notarised height
int32_t notarizedht,prevMoMheight; uint256 notarizedhash,txid;
uint64_t AmountToPay=0,ret=0;
notarizedht = komodo_notarized_height(&prevMoMheight,&notarizedhash,&txid);
// dont think this can happen, just sanity check.
if ( height == notarizedht )
{
fprintf(stderr, "komodo_notarypayamount failed notarized height = height\n");
return(0);
}
// how many block since last notarisation.
int32_t n = height - notarizedht;
fprintf(stderr, "blocks since last notarisation: %i\n",n);
@@ -1851,7 +1857,7 @@ uint64_t komodo_notarypay(CMutableTransaction &txNew, std::vector<int8_t> &Notar
//fprintf(stderr,"%02x",ptr[i+1]);
}
ptr[34] = OP_CHECKSIG;
//fprintf(stderr," set notary %i PUBKEY33 into vout[%i]\n",NotarisationNotaries[n],n+1);
//fprintf(stderr," set notary %i PUBKEY33 into vout[%i] amount.%lu\n",NotarisationNotaries[n],n+1,AmountToPay);
txNew.vout[n+1].nValue = AmountToPay;
total += txNew.vout[n+1].nValue;
}